p^2+44p+4=0

Solution for p^2+44p+4=0 equation:

p^2+44p+4=0

a = 1; b = 44; c = +4;
Δ = b2-4ac
Δ = 442-4·1·4
Δ = 1920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1920}=\sqrt{64*30}=\sqrt{64}*\sqrt{30}=8\sqrt{30}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-8\sqrt{30}}{2*1}=\frac{-44-8\sqrt{30}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+8\sqrt{30}}{2*1}=\frac{-44+8\sqrt{30}}{2}
$